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Interesting
Probability
Questions
about the Tim Horton's "Roll Up the Rim to Win" Contest
Introduction: In 2006, I was interviewed by the St. Catharines Standard
to answer some probability questions about the Tim Horton's "Roll Up
the Rim to Win" Contests. Since I thought many people wants to know
some of these probabilities, I set up this webpage and create some
interesting questions with help of my student Tomas Farrar, and even
wrote a Java applet to simulate the 2006
game. (You need the free
Java software to run it.) However, after that year, Tim
Horton's no longer disclosed the number of big prices for each cup
size. Therefore, it is no longer possible to calculate the odds for
each cup size. Therefore some answers to the questions in 2006 does
not apply to 2013. Nevertheless, I have written a JavaScript
application for the 2013 game which can
be run in more platforms and will continue to answer probability
questions about the contest. Due to the popularity of this contest,
I will continue to update this page every year. If you have an
interesting probability question to ask, you may email me at
.
-
The joke around my office is that i'm rather unlucky when
i comes to winning at this contest. Right now i am 0
for 15 this year (if i'm correct i'm only about 6.5% likely
to be in that situation). Last year i went 1 for
28. Combined i'm 1 for 43. I have some questions
in regards to how i would go about calculating the odds for
some of the following:
1) As the events are not completely independent, do my odds
of winning increase every time i roll up a loser? If so,
what are my odds of winning on my next cup?
- While the events are not completely independent, the
large number of cups in the contest (130025160 in Ontario)
means that you will improve your chance by very little. For
example, let say you are already in the middle of the
contest, and you roll up one more loser. Then your chance of
winning the next one will increase slightly by about
0.0000008% and therefore the events are essentially
independent.
2) The contest odds this year were the same as last year
(1 for 6) how would i combine my stats for these two years, or
can I even do this with any certainty?
- For the reason I explained in question 1, you can
combine these two years together. In your case, the
probability of going 0 for 15 is (5/6)^15=6.49% and the
probability of going 1 for 43 or 0 for 43 are 0.34% and
0.04% respectively. So assuming 10% people in Canada
(3500000) join the competition and have at least 43 coffees
in these two years, then about 11851 people share the
same experience with you and 1378 people do worst than you.
3) I would assume that is this case the events are in
fact independent, but what are the odds of me going 1 for 28
(or worse) every year?
- The chance is 0.04^n where n is the number of years.
4) How much of a factor does the cup distribution play at
a municipal level (in order words, do my odds change by buying
a coffee at a downtown location vs a suburban location)?
- While we do not have any information about it, it
probably should not matter for the small prices; there is no
reason to believe that Tim Horton's want to make people
angry. But for the large prices, there is a significant
difference, even though the chance of winning is very slim
anyway.
-
I'm curious though, i understand the formula to calculate
going 0 for X, but i can't seem to figure out how you
calculated going 1 for 43? (or any number of winners
for any number of cups for that matter)
- Assuming independence, the distribution of
the number of winners in X cups is actually Binomial(X,1/6).
This means that the probability of getting K winners is
given by
which is the product of the number of ways to
choose K winners from X, times the probability of getting K
winners in a particular arrangements.
-
In the video here,
it seems that the chance of winning with a small cup is way
too small (4 out of 38). Is there enough evidence to
conclude that the true odds of winning for small cups is
actually smaller than 1 in 6, as one suspects? Don't they
want to encourage you to buy a bigger cup so that they can
make more money?
- No. In fact, assuming that the true odds for small cups
is in fact 1 in 6, the probability that you have less than
or equal to 4 winners out of 38 is 21.78%,
which is not small enough to suspect that the assumption is
wrong (or "reject the null hypotheses" in statistics, which
typically requires a "p-value" less than 5%). What that
means is that assuming that Tim Horton's did not lie and
that say 10000 people have 38 small cups, you will find
around 2178 of them sharing the same experience (or worse),
which is not a small number.
-
1. Does 1 in 6 odds mean you can expect to win something
for every six cups you buy? Why not? How do you explain the
Timmies customer with 20 cups and no wins?
- No. It only means that in the long run if you buy a large
number of coffee, say 600 cups, you are expected to win
around 100 times. However, anything can happen if you only
buy 6. Nevertheless, you can still calculate the chance of
winning any number of times and see how lucky or unlucky you
are. For example, there is a probability of 2.61% that you
have no wins in 20 cups. With so many people buying more
than 20 cups during the contest, you will surely find a fair
number of unlucky people.
2. Are your odds of winning better if you buy a bigger cup?
Why or why not?
- They have not disclosed this information for years now
(it was available in the 2006 contest). So we don't know the
actual odds anymore.
3. Are your odds better if you live in certain parts of
Canada? Why or why not?
- It depends on what odds you are talking about. If you
are talking about small prizes (coffee, donuts, etc), they
don't disclose it but it is reasonable to assume that the
odds are 1 in 6 everywhere. But for large prizes, there are
some differences. For example, your chance of winning a car
is highest in Atlantic Province, which almost doubles that
in Alberta, Saskatchewan, Manitoba, Northwest Territories
& Yukon. USA has the best odds for the MasterCard (about
10% better than the worst in Quebec) and Tim Cards
(slightly). For the Grills, Ontario has a slight edge.
(All Questions pertain to Western & Southern Ontario only.)
-
How many coffees would you have to buy before you would
expect to win one Toyota RAV4 on average.
-
What is the average cash worth of a Roll Up the Rim
cup?
- Approximately 16-18
cents, depending on when the "coffee prices" are redeemed (earn another chance to win if
redeemed before the end of the contest). However, if you are like me,
who don't consider a coffee or a donut a "real prize", then
the worth drops dramatically to about 2 cents only.
-
True or False: you are more likely to win a RAV4 on an
extra-large cup than any other.
- False. Your chances of
winning a RAV4 are lowest on an Extra-Large (about 1 in 16
million). You are 36% more likely to win on a Large than an
Extra-Large, and 72% more likely to win on a Medium than an
Extra-Large. However, note that the average cash worth of a
cup is only about 0.2 cents better on a Medium than on an
Extra-Large. (My thoery to this advantage / unfairness is
that they might have a slightly higher profit margin when
they sell a medium cup and this is a strategy to motivate
someone (like me) to buy a medium. Imagine you drank an
extra large coffee in the morning, how likely are you going
to drink another one in the afternoon?)
-
If I won a coffee prize, based on the answer of the previous
question, should I then redeem it for a medium coffee over an
extra-large coffee?
- The answer of this
question depends on whether you really enjoy coffee or you
simply want a "real prize". Since the average cash
worth of a cup is only about 0.2 cents better on a Medium
than on an Extra-Large, if you really enjoy coffee, an
extra-large coffee is definitely worth more than the 0.2
cents (or the tiny extra winning chance of a medium cup).
However, if you don't really enjoy coffee, you should take
that extra winning chance of a medium cup, no matter how
small it is!
-
What if the contest has three days left and there is one
more RAV4 to be won in Southern Ontario? How do your chances
of winning a RAV4 compare to at the beginning of the
contest?
- Your probability of
winning a RAV4 on a cup is now slightly better than 1 in 4
million. You are now about 3 times as likely to win a RAV4
as at the beginning of the contest.
-
How do my chances of winning a RAV4 on a single cup compare
to winning the Lotto 6/49 Jackpot?
- The probabilities are
very similar: about 1 in 14 million for the Lotto 6/49 Big
Jackpot, and about 1 in 11 million for the RAV4. You are
thus about 23% more likely to win a RAV4 on a single play
than a Lotto 6/49 Jackpot.
-
What is the probability of buying 100 cups and not winning
any prize?
- The probability is about
1 in 130,000 - so you can count yourself very unlucky if
this happens!
-
What is the probability of winning a "real prize" (i.e. a
BBQ, $1000 cash, Plasma TV, or RAV4) if you buy 10,000
cups?
- The probability is still
about 1/3 (34.7%) of not winning.
-
How many cups would you have to buy to have a greater than
50% chance of winning a "real prize"?
- You would have to buy
16,246 cups.
-
If you bought a coffee for yourself and three co-workers,
what is the probability that all four of you would win a
prize?
- The probability is about
0.000152, or 1 in 6577.
The calculations for the the 2006
contest were done with the help of my student Tomas Farrar.